A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright interferenc

Question

A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright interference fringes on the screen are separated by 1.56 cm, what is the wavelength of the laser light

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Thanh Thu 2 months 2021-07-31T22:19:45+00:00 1 Answers 1 views 0

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    2021-07-31T22:20:46+00:00

    Answer:

    7.55\times 10^{-7} m

    Explanation:

    We are given that

    d=0.23 mm=0.23\times 10^{-3} m

    1mm=10^{-3} m

    Screen is placed  from the slits at distance ,L=4.75 m

    The bright interference fringes on the screen are separated  by 1.56 cm.

    \Delta y=1.56 cm=1.56\times 10^{-2} m

    1 m=100 cm

    We have to find the wavelength of laser light.

    We know that

    \Delta y=\frac{\lambda L}{d}

    Substitute the values

    1.56\times 10^{-2}=\frac{\lambda\times 4.75}{0.23\times 10^{-3}}

    \lambda=\frac{1.56\times 10^{-2}\times 0.23\times 10^{-3}}{4.75}

    \lambda=7.55\times 10^{-7} m

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