A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless su

Question

A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.

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Cherry 5 months 2021-08-27T12:43:01+00:00 1 Answers 6 views 0

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    2021-08-27T12:44:29+00:00

    Answer:

    The speed of the knife after passing through the target is 9.33 m/s.

    Explanation:

    We can find the speed of the knife after the impact by conservation of linear momentum:

     p_{i} = p_{f}

     m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}}

    Where:

     m_{k}: is the mass of the knife = 22.5 g = 0.0225 kg

     m_{t}: is the mass of the target = 300 g = 0.300 kg

     v_{i_{k}}: is the initial speed of the knife = 40.0 m/s

     v_{i_{t}} : is the initial speed of the target = 2.30 m/s

    v_{f_{k}}: is the final speed of the knife =?

     v_{f_{t}} : is the final speed of the target = 0 (it is stopped)

    Taking as a positive direction the direction of the knife movement, we have:

     m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}}  

     v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s

    Therefore, the speed of the knife after passing through the target is 9.33 m/s.

    I hope it helps you!              

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