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## a jeep start from the state of rest .if ots velocity became 60km/hr in 15 min. (i) what is the acceleration of the jeep?(ii) what is the

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## Answers ( )

Explanation:Here,

Convertingthequantitiesintoitsstandardform:→ v = 60 km/h

→ v = ( 60 × ) m/s

→ v = ( 10 × ) m/s

→ v = m/s

→

v = 16.66 m/sAlso,

→ t = 15 minutes

→ t = (15 × 60) seconds

→

t = 900 secondsCalculatingacceleration:★

v=u+at→ 16.66 = 0 + 900a

→ 16.66 – 0 = 900a

→ 16.66 = 900a

→ = a

→

0.0185 m/s² = a∴Accelerationis0.0185 m/s².## _________________________

Calculatingdistancecovered:★v²–u²=2as→ (16.66)² – (0)² = 2 × 0.0185 × s

→ 277.5556 – 0 = 0.037s

→ 277.5556 = 0.037s

→ = s

→

7501.50 m = s∴Distancecoveredis7501.50 m.