A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans. If we choose a jelly bean, then another jelly bean with

Question

A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans.
If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?

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Adela 2 days 2021-07-22T19:23:11+00:00 1 Answers 2 views 0

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    2021-07-22T19:24:34+00:00

    Answer:

    the probability is 5 ÷ 51

    Step-by-step explanation:

    The computation of the probability is shown below:

     = green jelly beans ÷ total jelly beans × remaining jelly beans ÷ remaining total jelly beans

    =  6 ÷ 18 × 5 ÷ 17

    = 30 ÷ 306

    = 5 ÷ 51

    Hence, the probability is 5 ÷ 51

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