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A hydrogen line in a star’s spectrum has a frequency of 6.17×10^14 Hz when stationary. In Rigel’s spectrum, it is shifted
Question
A hydrogen line in a star’s spectrum
has a frequency of 6.17×10^14 Hz
when stationary. In Rigel’s spectrum,
it is shifted downward by 4.26×10^10
Hz. What is Rigel’s velocity relative
to us?
PLS HELP!
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Physics
3 years
2021-08-28T13:07:14+00:00
2021-08-28T13:07:14+00:00 1 Answers
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Answers ( )
Answer: V = 4.35 × 10^12 m/s
Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.
Fo = (c ) / ( c – Vs) × f
Fo/f = (c ) / ( c – Vs)
4.26 × 10^10 = (3×10^8) 6.17×10^14/(3×10^8 – V)
4.26×10^10/6.17×10^14 = (3×10^8)/(3×10^8 – V)
6.9×10^-5 = (3×10^8)/(3×10^8 – V)
Cross multiply
20713.13 – 6.9×10^-5V = 3×10^8
Collect the like terms
6.9×10^-5V = 3×10^8 – 20713.13
6.9×10^-5V = 299979286.9
V = 299979286.9/6.9×10^-5
V = 4.3475 × 10^12 m/s
Therefore, Rigel’s velocity relative to us is 4.3475 × 10^12 m/s