“A hydraulic system is used to lift a” 51 kg “motor in a garage. If the motor sits on a piston of area” 0.25 m2, “and a force is applied to

Question

“A hydraulic system is used to lift a” 51 kg “motor in a garage. If the motor sits on a piston of area” 0.25 m2, “and a force is applied to a piston of area” 84 cm2, “what is the minimum force that must be applied to lift the motor in units of N?”

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Thông Đạt 4 years 2021-08-28T01:14:51+00:00 1 Answers 10 views 0

Answers ( )

  1. Ben
    0
    2021-08-28T01:16:19+00:00
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    Answer:

    Explanation:

    Given

    mass of motor m=51\ kg

    Area of piston A_1=0.25\ m^2

    Area of Piston 2 is A_2=84\ cm^2

    Weight of motor F_1=m\cdot g=51\times 9.8

    F_1=499.8\ N

    If F_2 is the force applied on the 2 nd piston

    According Pascal law Pressure at both the ends are equal

    \frac{F_1}{A_1}=\frac{F_2}{A_2}

    \frac{499.8}{0.25}=\frac{F_2}{84}

    F_2=167.93\ kN

    F_2=167.93\times 10^3\ N    

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