A hydraulic lift raises a 2 000-kg automobile when a 500-N force is applied to the smaller piston. If the smaller piston has an area of 10 c

Question

A hydraulic lift raises a 2 000-kg automobile when a 500-N force is applied to the smaller piston. If the smaller piston has an area of 10 cm2, what is the cross-sectional area of the larger piston?​

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King 7 months 2021-07-15T01:24:36+00:00 1 Answers 23 views 0

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    2021-07-15T01:25:50+00:00

    Answer:

    Explanation:

    ratio of the forces is equal to the ratio of the surface areas

    which is another way of saying the pressure is constant in the system

    2000(9.8) / 500 = A / 10

    A = 2000(9.8)(10) / 500 = 392 cm²

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