A house brick has a volume of 1900 cm³ and a weight in air of 80N.What is its apparent weight in water?The density of water is 1.00 g cm³?​

Question

A house brick has a volume of 1900 cm³ and a weight in air of 80N.What is its apparent weight in water?The density of water is 1.00 g cm³?​

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Tryphena 3 months 2021-08-25T17:18:00+00:00 1 Answers 2 views 0

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    2021-08-25T17:19:57+00:00

    Answer:

    61 N

    Explanation:

    We’ll begin by calculating the mass of the brick when placed in water. This can be obtained as follow:

    Volume of brick = 1900 cm³

    Density of water = 1 g/cm³

    Mass of brick in water =…?

    Density = mass / volume

    1 = mass of brick in water / 1900

    Cross multiply

    Mass of brick in water = 1 × 1900

    Mass of brick in water = 1900 g

    Next, we shall convert 1900 g to Kg.

    1000 g = 1 Kg

    Therefore,

    1900 g = 1900 g × 1 Kg / 1000 g

    1900 g = 1.9 Kg

    Next, we shall determine the weight in water. This can be obtained as follow:

    Mass (m) = 1.9 Kg

    Acceleration due to gravity (g) = 10 m/s²

    Weight (W) =?

    W = m × g

    W = 1.9 × 10

    W = 19 N

    Thus, the weight of the brick in water is 19 N.

    Finally, we shall determine the apparent weight of the brick in water. This can be obtained as follow:

    Weight in air = 80 N

    Weight in water = 19 N

    Apparent weight =?

    Apparent weight = weight in air – weight in water

    Apparent weight = 80 – 19

    Apparent weight = 61 N

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