A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The coefficient

Question

A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The coefficient of kinetic friction between the box and the floor is 0.23. What is the box’s launch speed?

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Philomena 5 months 2021-08-13T09:29:18+00:00 1 Answers 18 views 0

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    2021-08-13T09:30:30+00:00

    Answer:

    ugmd = 1/2 kx²

    d = (1/2 kx²) / (ugm)

    = (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

    = 7.4 m

    ugmd = 1/2 mv²

    v = √2ugd

    = √(2(0.23)(9.81 m/s²)(7.4 m)

    = 5.8 m/s

    Explanation:

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