## A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) If the goalie

Question

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) If the goalie catches the puck with his glove in a time of 2.33 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck?

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Physics
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2021-07-22T06:12:19+00:00
2021-07-22T06:12:19+00:00 1 Answers
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## Answers ( )

Answer:

2991.42 N

Explanation:

For this problem, we’ll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

final momentum; p2 = 0, because final velocity is 0 m/s

Thus,

impulse = p1 – p2= 6.97 – 0 = 6.97 kg.m/s

Finally, impulse= Force x time,

Thus, Force = Impulse/time

Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N