A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) If the goalie

Question

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) If the goalie catches the puck with his glove in a time of 2.33 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck?

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Mộc Miên 2 weeks 2021-07-22T06:12:19+00:00 1 Answers 1 views 0

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    2021-07-22T06:14:04+00:00

    Answer:

    2991.42 N

    Explanation:

    For this problem, we’ll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

    initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

    final momentum; p2 = 0, because final velocity is 0 m/s

    Thus,

    impulse = p1 – p2= 6.97 – 0 = 6.97 kg.m/s

    Finally, impulse= Force x time,

    Thus, Force = Impulse/time

    Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N

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