A hammer taps on the end of a 4.10-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pulses of sou

Question

A hammer taps on the end of a 4.10-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. The pulses are separated in time by 11.1 ms .

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Linh Đan 4 years 2021-08-14T22:31:13+00:00 1 Answers 5 views 0

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  1. Maris
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    2021-08-14T22:32:13+00:00
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    Answer:

    Speed of sound inside metal is ≅ 8200 \frac{m}{s}

    Explanation:

    Given :

    Length of metal bar x = 4.10 m

    From general velocity equation,

     v = \frac{x}{t}

    Where v = speed of sound in air = 343 \frac{m}{s}

    For finding time from above equation,

      t = \frac{x}{v}

     t = \frac{4}{343}

    t = 0.01166 sec

    Since pulses are separated by  t_{o} =  11.1 \times 10^{-3} = 0.0111 sec

    So we take time difference,

    \Delta t = t_{} -t_{o} = 0.0005

    So speed of sound in metal is,

     v = \frac{x}{\Delta t }

     v = \frac{4.10}{0.0005}

     v = 8200 \frac{m}{s}

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