A haloalkane ‘X’ if heated with sodium metal in presence of dry ether produces 2,3 – dimethyl butane as major product Identif

Question

A haloalkane ‘X’ if heated with sodium metal in presence of dry ether produces
2,3 – dimethyl butane
as major product
Identify x with chemical reaction.​

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Trung Dũng 6 months 2021-07-26T08:50:41+00:00 1 Answers 208 views 0

Answers ( )

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    2021-07-26T08:51:57+00:00

    Answer:

    2 halo – propane

    Explanation:

    We are told that a halo alkane is heated with sodium in the presence of dry ether to produce 2,3 – dimethyl butane.

    Now, according to Wurtz reaction this formation from heating with sodium in the presence of dry ether is done by 2 alkyl halides in the form of;

    2RX + 2Na → R−R + 2Na+X−

    Now, formula for 2,3 dimethyl butane is (CH₃)₂CHCH(CH₃)₂

    Thus, from the Wurtz reaction, we can write that;

    2RX + 2Na → (CH₃)₂CH – CH(CH₃)₂ + 2Na+X−

    So, R = (CH₃)₂CH

    This means the original halo alkane has 3 carbon atoms and thus, we can say it is 2 halo – propane.

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