A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Find the 95% confidence interv

Question

A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Find the 95% confidence interval of the mean score of all bowlers.

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Dâu 3 months 2021-08-06T09:35:22+00:00 1 Answers 7 views 0

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    2021-08-06T09:37:18+00:00

    Answer:

    CI=189.5,194.5

    Step-by-step explanation:

    From the question we are told that:

    Sample size n=40

    Mean \=x =192

    Standard deviation\sigma=8

    Significance Level \alpha=0.05

    From table

    Critical Value of Z=1.96

    Generally the equation for momentum is mathematically given by

     CI =\=x \pm z_(a/2) \frac{\sigma}{\sqrt{n}}

     CI =192 \pm 1.96 \frac{8}{\sqrt{40}}

     CI=192 \pm 2.479

     CI=189.5,194.5

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