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## A generator has a square coil consisting of 269 turns. The coil rotates at 113 rad/s in a 0.222-T magnetic field. The peak output of the gen

Question

A generator has a square coil consisting of 269 turns. The coil rotates at 113 rad/s in a 0.222-T magnetic field. The peak output of the generator is 79.2 V. What is the length of one side of the coil?

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Physics
3 years
2021-08-22T01:09:57+00:00
2021-08-22T01:09:57+00:00 2 Answers
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## Answers ( )

Answer:Explanation:number of turns, n = 269

angular velocity, ω = 113 rad/s

magnetic field, B = 0.222 T

Voltage, V = 79.2 V

Let the area of the coil is A and the side of the square is s.

The maximum emf generated by the coil is

V = n x B x A x ω

79.2 = 269 x 0.222 x A x 113

A = 0.01174 m²

so, s x s = 0.01174

s = 0.108 m

Thus, the side of the square coil is 0.108 m.

Answer:length of one side of the coil is 0.1083 mExplanation:given datano of turn = 269

coil rotates = 113 rad/s

magnetic field = 0.222-T

peak output = 79.2 V

solutionwe will apply here formula for maximum emf induced in a coil that is

εo = N × A × B × ω ……………………1

and here Area A = l²

so

l =

put here value of A from equation 1

I =

put here value and we will get

l =

l = 0.1083 m