A gas occupies 0.67 L at 350 K. What temperature is required to reduce the volume to 0.21 L *

Question

A gas occupies 0.67 L at 350 K. What temperature is required to reduce
the volume to 0.21 L *

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Nho 2 weeks 2021-07-19T21:21:35+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-19T21:23:12+00:00

    Answer:

    109.7K

    Explanation:

    Using Charles law equation as follows;

    V1/T1 = V2/T2

    Where;

    V1 = initial volume (L)

    V2 = final volume (L)

    T1 = initial temperature (K)

    T2 = final temperature (K)

    According to the information provided in this question;

    V1 = 0.67L

    V2 = 0.21L

    T1 = 350K

    T2 = ?

    Using the formula above;

    0.67/350 = 0.21/T2

    0.001914 = 0.21/T2

    0.001914T2 = 0.21

    T2 = 0.21/0.001914

    T2 = 109.7K

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