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A gas has a pressure of 500.0 Torr at 35.0 °C. What is the temperature at standard pressure?
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Answers ( )
Answer:
466.65 K
Explanation:
Using the formula of Pressure law,
P/T = P’/T’……………….. Equation 1
Where P = Intial pressure of gas, T = Initial temperature of gas, P’ = Final pressure of gas, T’ = Final temperature of gas.
make T’ The subeject of equation 1
T’ = (P’T)/P………………. Equation 2
From the question,
Given: P = 500 Torr = (500×133.322) N/m² = 66661 N/m², T = 35°C = (35+273) = 308 K, P’ = 101000 N/m²( Standard pressure)
Substitute these values into equation 2
T’ = (101000×308)/66661
T’ = 466.65 K