A gas goes from 1L at 273 K to 2 L when heated. What is the new temp?

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A gas goes from 1L at 273 K to 2 L when heated. What is the new temp?

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Verity 4 years 2021-09-02T08:05:58+00:00 1 Answers 7 views 0

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    2021-09-02T08:07:33+00:00

    Answer:

    Given : Diatomic molecule at 273K

    ‘q’ absorbed = positive = +100Cal = 100 x 4.184J = 418.4J

    ‘W’ done by system = negative = -209J

    By first law of thermodynamics;

    ΔU = q + W = 418.4 + (-209) = 209.4J

    We know for diatomic molecule Cv=25R and CvΔT=ΔU

    CvΔT=209.4

     25RΔT=209.4

    ΔT=5R209.4×2

    And, Heat exchange=Cm×ΔT 

    where; Cm is molar heat capacity

    Cm=ΔTHeat Exchange

    substituting values for Heat Exchange = 418.4 and ΔT=5R209.4×2

    Cm=5R

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