A gardener fills a 2 1/2 cubic foot wheelbarrow 2/3 of the way without soil weight 75.25 pounds. What is the weight of the soil un wheelbarr

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1. Volume of wheelbarrow , V = 2 1/2 ft³ = 5/2 ft³.

   Volume of soil in wheelbarrow , [tex]v = \dfrac{5}{3}\ ft^3[/tex] .

   Mass of soil in wheelbarrow , m = 75.25 pounds.

   Now, volume left , [tex]v’=\dfrac{5}{6}\ ft^3[/tex] .

   Let, mass of  soil un wheelbarrow is x.

   [tex]x=\dfrac{\dfrac{5}{6}\times 75.25}{\dfrac{5}{3}}\\\\x=37.625\ pounds[/tex]

   Hence, this is the required solution.

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