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A game of chance involves rolling a 16-sided die once. If a number from 1 to 3 comes up, you win 4 dollars. If the number 4 or 5 comes up, y
Question
A game of chance involves rolling a 16-sided die once. If a number from 1 to 3 comes up, you win 4 dollars. If the number 4 or 5 comes up, you win 7 dollars. If any other number comes up, you lose. If it costs 5 dollars to play, what is your expected net winnings
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Mathematics
1 year
2021-08-29T20:59:35+00:00
2021-08-29T20:59:35+00:00 1 Answers
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Answer:
-$1.8
or loss of $1.8
Step-by-step explanation:
Given the following parameters, we have
The probability of winning $4 is 3/16
The probability of winning $7 is 2/16
The probability of losing $5 is 11/16
E(X) = (4 * 3/16) + (7 * 2/16) + (-5 * 11/16)
= 12/16 + 14/16 – 55/16
= -29/16
= -1.8
Hence, your expected net “winnings” would be -$1.8. That’s an expected loss of $1.8.