A galvanometer coil having a resistance of 20 Ω and a full-scale deflection at 1.0 mA is connected in series with a 4980 Ω resistance to bui

Question

A galvanometer coil having a resistance of 20 Ω and a full-scale deflection at 1.0 mA is connected in series with a 4980 Ω resistance to build a voltmeter. What is the maximum voltage that this voltmeter can read?

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Verity 1 year 2021-09-02T02:23:24+00:00 2 Answers 48 views 0

Answers ( )

    0
    2021-09-02T02:24:59+00:00

    Answer:

    5 V

    Explanation:

    The maximum voltage the voltmeter  can read will be the voltage drop across the 20 Ω resistance and the voltage drop across the 4980 Ω resistance.

    V’ = Ir +IR……………….. equation 1

    Where V’ = Maximum voltage the voltmeter can read, I = current, r = resistance of the galvanometer coil, R = The resistance connected in series to the galvanometer.

    Given: I = 1 mA = 0.001 A, r = 20Ω, R = 4980Ω

    Substitute into equation 1

    V’ = 20(0.001)+4980(0.001)

    V’ = 0.02+4.98

    V’ = 5 V

    0
    2021-09-02T02:25:01+00:00

    Answer:

    Explanation:

    E = IR + Ir

    Where,

    I = current

    = 1 mA

    = 0.001 A

    R = 4980 Ω

    Internal resistance, r = 20 Ω

    Maximum voltage, E = 0.001 × 4980 + 0.001 × 20

    = 4.98 + 0.02

    = 5 V

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