A force Fx=cx-3.00×2 acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c a constant. At x = 0

Question

A force Fx=cx-3.00×2 acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c a constant. At x = 0, the virus’s kinetic energy is 20.0 J, while at x = 3.00 m, it is 11.0 J. Find c.

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Thu Nguyệt 6 months 2021-08-14T23:46:49+00:00 1 Answers 2 views 0

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    2021-08-14T23:47:49+00:00

    Answer:

    4

    Explanation:

    We are given that

    F_x=cx-3x^2

    K.E at x=0 m=20 J

    K.E at x=3 m=11 J

    We have to find the value of c.

    By work energy theorem

    Work done=Change in kinetic energy

    W=\int_{0}^{3} Fdx=\int_{0}^{3}(cx-3x^2)dx

    W=[\frac{cx^2}{2}-x^3]^{3}_{0}

    W=\frac{9c}{2}-27

    \Delta K=11-20=-9 J

    -9=\frac{9c}{2}-27

    -9+27=\frac{9c}{2}

    18=\frac{9c}{2}

    c=\frac{2}{9}\times 18=4

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