A force =(16.8N/s)t is applied to an object of m=45.0kg. Ignoring friction, how far does the object travel from rest in 5.00s?

Question

A force =(16.8N/s)t is applied to an object of m=45.0kg. Ignoring friction, how far does the object travel from rest in 5.00s?

in progress 0
Amity 3 months 2021-08-18T07:12:37+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-18T07:14:34+00:00

    Answer:

    Explanation:

    a = F/m = 16.8t/45 = 0.373*t

    v = ∫a*dt = ∫(0.373*t)dt = 0.1865*t²

    x = ∫v*dt = 0.1865∫(t²)dt = 0.062*t³

    For t = 5.0 sec,

    x = 0.062*(5)^3 = 7.75 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )