a fly undergoes a displacement of – 5.80 while accelerating at -1.33 m/s^2 for 4.22 s. what was the initial velocity of the fly?

Question

a fly undergoes a displacement of – 5.80 while accelerating at -1.33 m/s^2 for 4.22 s. what was the initial velocity of the fly?

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Thanh Hà 6 months 2021-08-18T16:44:08+00:00 1 Answers 0 views 0

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    2021-08-18T16:45:17+00:00

    Answer:

    v_i = 1.44\frac{m}{s}

    Explanation:

    The computation of the initial velocity of the fly is shown below:-

    But before that we need to do the following calculations

    For 4.22 seconds

    \bar v = \frac{-5.80 m}{4.22 s}

    = -1.37\frac{m}{s}

    For uniform acceleration

    \bar v = \frac{v_i +v_f}{2}

    = v_i + v_f

    = -2.74\frac{m}{s}

    With initial and final velocities

    = -1.33\frac{m}{s^2}

    = \frac{v_i +v_f}{4.22s}

    = -v_i + v_f

    = -5.61\frac{m}{s}

    So, the initial velocity is

    v_i = 1.44\frac{m}{s}

    We simply applied the above steps to reach at the final solution i.e initial velocity

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