A flat circular loop of wire of radius 0.50 m that is carrying a 2.0-A current is in a uniform magnetic field of 0.30 T. What is the magnitu

Question

A flat circular loop of wire of radius 0.50 m that is carrying a 2.0-A current is in a uniform magnetic field of 0.30 T. What is the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field

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Sapo 6 months 2021-08-21T21:53:44+00:00 1 Answers 0 views 0

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    2021-08-21T21:55:07+00:00

    Answer:

    The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

    Explanation:

    Given;

    radius of the circular loop of wire = 0.5 m

    current in circular loop of wire = 2 A

    strength of magnetic field in the wire = 0.3 T

    τ = μ x Bsinθ

    where;

    τ is the magnitude of the magnetic torque

    μ is the dipole moment of the magnetic field

    θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90

    μ = IA

    where;

    I is current in circular loop of wire

    A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²

    μ = 2 x 0.7885 = 1.571 A.m²

    τ = μ x Bsinθ =  1.571 x 0.3 sin(90)

    τ = 0.4713 J

    Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

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