A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming no frictiona

Question

A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming no frictional forces, what was the initial velocity the fisherman gave the lure when he cast it?

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Hưng Khoa 4 weeks 2021-08-18T03:56:24+00:00 1 Answers 0 views 0

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    2021-08-18T03:58:17+00:00

    Answer:

    12.32 m/s

    Explanation:

    Using the formula of maximum height of a projectile,

    H = u²sin²Ф/2g………………. Equation 1

    Where H = maximum height, u = initial velocity, Ф = angle of projection, g = acceleration due to gravity

    make u the subject of the equation

    u = √(2Hg/sin²Ф)………… Equation 2

    Given: H = 2.3 m, Ф = 33°, g = 9.8 m/s²

    Substitute into equation 2

    u = √[(2×2.3×9.8)/sin²33°]

    u =√ [45.08/(0.545)²]

    u = 45.08/0.297

    u = √(151.785)

    u = 12.32 m/s

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