A dragster takes off from rest and crosses the finish line 320 m away. If the dragster is able to accelerate at 10LaTeX: \frac{m}{s^2}m s 2

Question

A dragster takes off from rest and crosses the finish line 320 m away. If the dragster is able to accelerate at 10LaTeX: \frac{m}{s^2}m s 2 then how long does it take to finish?

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Thành Đạt 3 months 2021-07-19T16:34:57+00:00 2 Answers 3 views 0

Answers ( )

    0
    2021-07-19T16:36:05+00:00

    Answer:

    t = 8 s

    Explanation:

    In order to find the time taken by the dragster we will use equations of motion. Here, we will use second equation of motion:

    s = Vi t + (1/2)at²

    where,

    s = distance covered = 320 m

    Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)

    t = time taken = ?

    a = acceleration of dragster = 10 m/s²

    Therefore,

    320 m = (0 m/s)t + (1/2)(10 m/s²)t²

    t² = (320 m)(2)/(10 m/s²)

    t = √(64 s²)

    t = 8 s

    0
    2021-07-19T16:36:08+00:00

    Answer:

    t = 8 s

    Explanation:

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