A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then run to end

Question

A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then run to end up 11.0 m south of her original starting point?

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Calantha 4 years 2021-07-29T02:56:21+00:00 1 Answers 39 views 0

Answers ( )

  1. Eirian
    0
    2021-07-29T02:57:23+00:00
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    Answer:

    \theta=19.03 SE

    Explanation:

    From the question we are told that:

    d_1=11.0m East

    d_2=28.0m 49 \textdegree west\ north

    d_3=10m south

    Generally the equation for Resolutions is mathematically given by

    d_x=-11-(-28sin49)

    d_x=10.132m

    Where

    d_y=-11-(28cos49)

    d_y=-29.37m

    Generally the equation for Direction is mathematically given by

    \theta=tan^{-1}(\frac{dx}{dy})

    \theta=tan^{-1}(\frac{10.132}{29.37})

    \theta=19.03 SE

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