A dog accelerates at 1.50 m/s2 to reach a velocity of 13.5 m/s while covering a distance of 49.3 m. What was his initial velocity?

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A dog accelerates at 1.50 m/s2 to reach a velocity of 13.5 m/s while covering a distance of 49.3 m. What was his initial velocity?

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Thu Cúc 7 months 2021-07-24T11:19:48+00:00 1 Answers 7 views 0

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  1. Sapo1
    0
    2021-07-24T11:21:45+00:00
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    Let v be the dog’s initial velocity. Then

    (13.5 m/s)^2 – v ^2 = 2 (1.50 m/s^2) (49.3 m)

    ==>   v ^2 = (13.5 m/s)^2 – 2 (1.50 m/s^2) (49.3 m)

    ==>   v = √((13.5 m/s)^2 – 2 (1.50 m/s^2) (49.3 m))

    ==>   v ≈ 5.86 m/s

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