A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board

Question

A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:

a. the force at the support point
b. the force at the left-hand end.

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Latifah 2 months 2021-08-03T16:26:26+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-08-03T16:28:10+00:00

    Answer:

    F_l=1140N

    Explanation:

    From the question we are told that:

    Lengthl=3.00m

    Support distance d=1.00m

    Weight of diver W_d=500N

    Weight of board W_b=280N

    Generally the equation for Total Torque is mathematically given by

     F_T=W_d-W_b

     F_T=F_d-f_b

     F_T=-280-500

     F_T=-780

     F_T=780

    Since we consider the horizontal axis

     \sum Y=0

     Fs-(\frac{1}{2}l*w_b)-(l-w_d)

     Fs-1.5*280-3*300=0

     F_s=1920N

    Therefore  the force at the support point  1.00m from the force at the left-hand

     F_l=F_s-F_l

     F_l=1920-780

     F_l=1140N

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