A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangularframe to prevent collapse. The rod can safe

Question

A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangularframe to prevent collapse. The rod can safely support a tensile stress of sallow. If d 5 0.5 in,l 5 8 ft, and sallow 5 20 kpsi, determine how much the rod must be stretched to develop thisallowable stress.

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RuslanHeatt 5 months 2021-08-24T21:57:04+00:00 1 Answers 6 views 0

Answers ( )

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    2021-08-24T21:58:51+00:00

    Answer:

    The stretched length is 0.18816 in.

    Explanation:

    Given that,

    Distance = 0.5 in

    length = 8 ft

    Tensile stress = 20 kpsi

    We need to calculate the stretched length

    Using formula of length

    \Delta L=\dfrac{PL}{AE}

    \Delta L=\sigma\times\dfrac{L}{E}

    Where, \sigma = Tensile stress

    L = length

    E = young’s modulus of aluminum

    Put the value into the formula

    \Delta L= 20\times10^3\dfrac{8}{10.2\times10^{6}}

    \Delta L= 0.01568\ ft

    \Delta L=0.01568\times12

    \Delta L=0.18816\ in

    Hence, The stretched length is 0.18816 in.

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