A cyclist accelerates from rest to 8 m/s in 3 seconds. How far did the cycles travel in 3 seconds?​

Question

A cyclist accelerates from rest to 8 m/s in 3 seconds. How far did the cycles travel in 3 seconds?​

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Nho 4 years 2021-07-23T19:58:30+00:00 2 Answers 13 views 0

Answers ( )

    0
    2021-07-23T19:59:39+00:00

    Answer:

     \boxed{\sf Distance \ travelled = 12 \ m}

    Given:

    Initial speed (u) = 0 m/s (Accelerates from rest)

    Final speed (v) = 8 m/s

    Time taken (t) = 3 seconds

    To Find:

    Distance travelled by cyclist (s)

    Explanation:

    From equation of motion of object moving with uniform acceleration in straight line we have:

     \boxed{ \bold{s =  (\frac{v + u}{2} )t}}

    By substituting value of v, u & t in the equation we get:

     \sf \implies s = ( \frac{8 + 0}{2} ) \times 3 \\  \\  \sf \implies s =  \frac{8}{2}  \times 3 \\  \\  \sf \implies s = 4 \times 3 \\  \\  \sf \implies s = 12 \: m

     \therefore

    Distance travelled by cyclist (s) = 12 m

    0
    2021-07-23T19:59:51+00:00

    Answer:

    s(distance) =36m

    Explanation:

    u(initial velocity) =0 m/s

    a =8 m/s^2

    t=3s

    s=ut+1/2at^2

    s=1/2(8)(3)^2

    s=1/2(8)(3)(3)

    s=4(9)

    s=36m

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