A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find this dista

Question

A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find
this distance.

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Delwyn 6 months 2021-09-03T17:53:51+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-03T17:55:09+00:00

    Answer:

    0.050 m

    Explanation:

    The strength of the magnetic field produced by a current-carrying wire is given by

    B=\frac{\mu_0 I}{2\pi r}

    where

    \mu_0=4\pi \cdot 10^{-7} H/m is the vacuum permeability

    I is the current in the wire

    r is the distance from the wire

    And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.

    In this problem, we have:

    I=1.41 A (current in the wire)

    B=5.61\mu T=5.61\cdot 10^{-6} T (strength of magnetic field)

    Solving  for r, we find the distance  from the wire:

    r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m

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