A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is a resultant

Question

A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is a resultant force of 3 N on the wire due to the interaction of the current and field, what is the magnetic field strength

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Adela 6 months 2021-07-29T16:24:01+00:00 1 Answers 4 views 0

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    2021-07-29T16:25:29+00:00

    Answer:

    0.2

    Explanation:

    F= BIL sin©

    3= B×10×1.5 sin90

    B=3/15

    B= 0.2

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