A cube of ice is taken from the freezer at -5.5 ∘C and placed in a 75-g aluminum calorimeter filled with 300 g of water at room temperature

Question

A cube of ice is taken from the freezer at -5.5 ∘C and placed in a 75-g aluminum calorimeter filled with 300 g of water at room temperature of 20.0 ∘C. The final situation is observed to be all water at 17.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333 kJ/Kg.

What was the mass of the ice cube?Express your answer to two significant figures and include the appropriate units.

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Cherry 1 year 2021-09-03T10:17:23+00:00 1 Answers 292 views 0

Answers ( )

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    2021-09-03T10:19:08+00:00

    Answer:

    Explanation:

    Let mass of ice cube taken out be m kg .

    ice will gain heat to raise its temperature from – 5.5° to 0° and then from 0° to 17° .

    Total heat gained = m x 2.1 x 5.5 + m x 333 + m x 4.186 x 17

    = (11.55 + 333 + 71.162 )m

    = 415.712 m kJ

    Heat lost by aluminium calorimeter

    = .075 x .9 x 3  

    = .2025 kJ

    Heat lost by water

    = .3 x 4.186 x 3

    = 3.7674

    Total heat lost

    = 3.9699 kJ

    Heat lost = heat gained

    415.712 m = 3.9699

    m = .0095 kg

    9.5 gm .

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