A constant voltage of 6.00 V has been observed over a certain time interval across a 3.00 H inductor. The current through the inductor, meas

Question

A constant voltage of 6.00 V has been observed over a certain time interval across a 3.00 H inductor. The current through the inductor, measured as 3.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 8.00 A at the end of the time interval. How long was this time interval?

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Delwyn 4 years 2021-07-21T07:50:06+00:00 1 Answers 36 views 0

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  1. Nick
    0
    2021-07-21T07:51:36+00:00
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    Answer:

    The time interval is 2.5 sec

    Explanation:

    Given:

    applied voltage V = 6 V

    Inductance L = 3 H

    Current change dI = 8 -3= 5 A

    From the formula of magnitude of induced emf in terms of inductance,

       V = L\frac{dI}{dt}

    For finding the time interval,

       dt = \frac{L dI}{V}

       dt = \frac{3 \times 5}{6}

       dt = 2.5 sec

    Therefore, the time interval is 2.5 sec

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