a compound decomposes by a first-order process. if 17.0% of the compound decomposes in 60.0 minutes, the half-life of the compound is

Question

a compound decomposes by a first-order process. if 17.0% of the compound decomposes in 60.0 minutes, the half-life of the compound is

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Lệ Thu 6 months 2021-07-31T03:31:27+00:00 1 Answers 21 views 0

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    2021-07-31T03:33:15+00:00

    Answer:

    the half-life of the compound is 223 minutes

    Explanation:

    Given the data in the question;

    compound decomposes by a first-order process,

    17% of compound decomposes in 60 minutes,

    the half-life of the compound = ?

    Since its a first order reaction, we use the expression;

    k = 1/t ln( Co/Cf )

    given that; t = 30 minutes, Cf = 1 – 17% of Co = 1 – 0.17 of Co = 0.83Co

    we substitute

    k = ( 1 / 60 min ) ln( Co / 0.83Co )

    k =  ( 1 / 60 min ) ln( 1 / 0.83 )

    k = 0.016667 × 0.186329578

    k = 0.003105555

    so get the half life;

    t_{1/2 = 0.693 / k

    we substitute

    t_{1/2 = 0.693 / 0.003105555

    t_{1/2 = 223.14 ≈ 223 minutes

    Therefore, the half-life of the compound is 223 minutes

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