A competitive go-cart driver is traveling 32 m/s. He sees a caution flag go up, so he slows at a rate of -1.5 m/s^2 in 10.8 s. What is his f

Question

A competitive go-cart driver is traveling 32 m/s. He sees a caution flag go up, so he slows at a rate of -1.5 m/s^2 in 10.8 s. What is his final velocity?

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Vodka 1 week 2021-07-23T00:09:16+00:00 1 Answers 1 views 0

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    2021-07-23T00:11:10+00:00

    Answer:

    15.8 m/s

    Explanation:

    The following data were obtained from the question:

    Initial velocity (u) = 32 m/s.

    Acceleration (a) = – 1.5 m/s²

    Time (t) = 10.8 s.

    Final velocity (v) =?

    Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:

    Acceleration (a) = [final velocity (v) – initial velocity (u)] / time (t)

    a = (v – u) /t

    With the above formula, we can obtain the final velocity of go-cart driver as follow:

    Initial velocity (u) = 32 m/s.

    Acceleration (a) = – 1.5 m/s²

    Time (t) = 10.8 s.

    Final velocity (v) =?

    a = (v – u) /t

    – 1.5 = (v – 32) / 10.8

    Cross multiply

    (v – 32) = –1.5 × 10.8

    v – 32 = – 16.2

    Collect like terms

    v = – 16.2 + 32

    v = 15.8 m/s

    Therefore, the final velocity of go-cart driver is 15.8 m/s.

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