A company manufacturing KMnO4 wants to obtain the highest yield possible. Two of their research scientists are working on a technique to inc

Question

A company manufacturing KMnO4 wants to obtain the highest yield possible. Two of their research scientists are working on a technique to increase the yield.

Both scientists started with 50.0 g of manganese oxide (MnO2).

What is the theoretical yield of potassium permanganate when starting with this 50.0 g MnO2?

The equation for the production of potassium permanganate is as follows:

2 MnO2 + 2 KOH + O2 → 2 KMnO4 + H2

You must show all work to receive full credit.

in progress 0
Farah 2 months 2021-07-25T16:51:16+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-25T16:53:04+00:00

    Answer:

    m_{KMnO_4}=90.9gKMnO_4

    Explanation:

    Hello there!

    In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

    m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2}  *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4

    Regards!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )