A compact fluorescent bulb is 17.0% efficient. How much energy input would be required for the bulb to produce 252 J of light energy?

Question

A compact fluorescent bulb is 17.0% efficient. How much energy input would be required for the bulb to produce 252 J of light energy?
What time of energy is the waste output and how much would be created?

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Farah 4 years 2021-08-21T16:53:35+00:00 1 Answers 173 views 0

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  1. Acacia
    0
    2021-08-21T16:54:49+00:00
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    Answer:

    1482.35J

    Explanation:

    Efficency=(output energy/input energy) x100

    17.0 =(252/input energy) x100

    input energy =100×252/17=1482.35J

    wasted energy=1482.35-252=1230.35J

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