A commuter backs her car out of her garage with an acceleration of 1.40 m/s2.A) How long does it take her to reach a speed of 2.00 m/s?B) If

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A commuter backs her car out of her garage with an acceleration of 1.40 m/s2.A) How long does it take her to reach a speed of 2.00 m/s?B) If she then breaks to a stop in 0.800 s, what is her deceleration?

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Thông Đạt 4 years 2021-07-28T06:54:57+00:00 1 Answers 25 views 0

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    2021-07-28T06:56:50+00:00

    Answer:

    (A) 1.43secs

    (B) -2.50m/s^2

    Explanation:

    A commuter backs her car out of her garage with an acceleration of 1.40m/s^2

    (A) When the speed is 2.00m/s then, the time can be calculated as follows

    t= Vf-Vo/a

    The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0

    = 2.00-0/1.40

    = 2.00/1.40

    = 1.43secs

    (B) The deceleration when the time is 0.800secs can be calculated as follows

    a= Vf-Vo/t

    = 0-2.00/0.800

    = -2.00/0.800

    = -2.50m/s^2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )