A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is 2.5 m. (The accele

Question

A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is 2.5 m. (The acceleration due to gravity is 9.8 m/s2m/s2 and the density of water is 1000 kg/m3kg/m3.) How much work (in Joules) is required to:

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Thiên Ân 4 years 2021-08-16T03:01:58+00:00 1 Answers 18 views 0

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  1. Helga
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    2021-08-16T03:03:06+00:00
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    Answer:

    Explanation:

    Diameter of pool = 12 m

    radius of pool, r = 6 m

    Total height raised, h = 3 + 2.5 = 5.5 m

    density of water, d = 1000 kg/m³

    Mass of water, m = Volume of water x density

    m = πr²h x d

    m = 3.14 x 6 x 6 x 5.5 x 1000

    m = 113040 kg

    Work = m x g x h

    W = 113040 x 9.8 x 5.5

    W = 6092856 J

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