A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A

Question

A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.8 T is directed along the positive z-direction, which is upward.

If the loop is removed from the field region in a time interval of 2.8 ms, find the average emf that will be induced in the wire loop during the extraction process.

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Tryphena 5 months 2021-08-15T00:57:32+00:00 1 Answers 23 views 0

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    2021-08-15T00:58:54+00:00

    Answer:

    The average induced emf is 29.06 V

    Explanation:

    Given;

    radius of the circular loop, r = 12.0 cm = 0.12 m

    magnetic field strength, B =  1.8 T

    time interval = 2.8 ms = 0.0028 s

    Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

    e.m.f =\frac{BA}{t}

    where;

    B is magnetic field

    A is area

    t is time

    substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

    e.m.f =\frac{1.8 *0.0452}{0.0028} = 29.06 \ V

    Therefore, the average induced emf is 29.06 V

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