A chemical breaks down in a flow-balanced, steady-state CFMR according to first-order reaction kinetics. At steady state, the upstream and d

Question

A chemical breaks down in a flow-balanced, steady-state CFMR according to first-order reaction kinetics. At steady state, the upstream and downstream concentration of the chemical are 15 mg/L and 5 g/m3. Water is being treated at a rate of 0.42 m3/sec. The volume of the tank is 500,000 liters. Assuming a first-order reaction, what is the rate constant

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Sapo 5 months 2021-09-05T10:15:34+00:00 1 Answers 0 views 0

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    2021-09-05T10:17:28+00:00

    Answer:

    k =0.101 \ min^{-1}

    Explanation:

    From the given information:

    The initial concentration of a chemical C_{AO} = 15 \ mg/L

    The final concentration is C_A = 5 \ g/m^3 = 5 mg/L

    Volume flow rate V_o = 0.42 \ m^3/sec

    Volume of the tank V = 500 000 L = 500 m³

    The time t is determined by using the formula:

    t= \dfrac{V}{V_o}

    t= \dfrac{500 \ m^3}{0.42 \ m^3/sec}

    t = 1190.47 sec

    t ≅ 19.8 min

    The rate of the decay constant is:

    kt= \dfrac{C_{AO}-C_{A}}{C_A} \\ \\ k = \dfrac{1}{19.8}( \dfrac{15-5}{5})

    k =0.101 \ min^{-1}

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