A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reaches to a regio

Question

A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reaches to a region in space with magnetic field of 0.05 (T) and experience a force of 8 (N) exerted by the magnetic field.
A- What is the angle between velocity of particle and magnetic field direction?
B- What is acceleration of charged particle while experiencing the force?

in progress 0
Kim Chi 6 months 2021-08-13T09:45:48+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-08-13T09:47:40+00:00

    Answer:

    Explanation:

    A ) Let the angle be θ between magnetic field and velocity of charged particle

    Force created on charged particle F

    = Bqv sinθ, B is magnetic field , q is charge , v is velocity of charged particle

    F = .05 x 2 x 10⁻⁶ x 10⁸ x sinθ

    8 = 10 sinθ

    sinθ = .8

    θ =  53°.

    B )

    acceleration = force / mass

    = 8 / 10⁻²⁰

    = 8 x 10²⁰ m / s²

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )