A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the particle moves

Question

A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.20 m at a speed of 2.0 m/s. what is the magnitude of the charge on the particle

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Thu Giang 3 years 2021-08-06T00:04:56+00:00 1 Answers 12 views 0

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  1. Vodka
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    2021-08-06T00:06:39+00:00
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    Answer:

    0.01 C

    Explanation:

    Applying,

    F = qvBsinФ……………. Equation 1

    Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф =  angle

    Since the charged particle noves in a circle,

    F = mv²/r…………….. Equation 2

    Where m = mass of the particle, v = velocity of the particle, r = radius of the  circle

    Substitute equation 2 into equation 1

    mv²/r = qvBsinФ

    make q the subject of the equation

    q = mv/(rBsinФ)…………. Equation 3

    Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)

    Substitute these values into equation 3

    q = (0.005×2)/(0.2×5×sin90°)

    q = 0.01/(1)

    q = 0.01 C

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