A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the elect

Question

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

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Thạch Thảo 7 months 2021-08-08T14:09:58+00:00 1 Answers 8 views 0

Answers ( )

    0
    2021-08-08T14:11:56+00:00

    Answer:

    0.027 J

    Explanation:

    The formula of the potential energy in electrostatic (U) is

    U = q \times E \times d

    The values given in the question are

    Charge : q = 4.5 \times 10^{-5} C

    Electric Field strength : E = 2.0 \times 10^{4} N/C

    Distance : d  is 0.030 m

    Insert in the formula , will give us

    U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

    Further solving it

    U = 0.027 J

    Which is the required answer.

    Thanks

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