A charge of +3.0 µC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energy is require

Question

A charge of +3.0 µC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energy is required to bring a charge of 25µC from infinity to the center of the circle?

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Diễm Kiều 2 months 2021-07-31T21:20:52+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-31T21:22:33+00:00

    Answer:

    The energy required is  E= 3.375*10^6J

    Explanation:

    From the question we are told that

      The charge is q_1 = 3.0 \mu C = 3.0*10^{-6}C

      The radius is r = 20cm = \frac{20}{100} = 0.2m

       The second charge is q_2 = 25 \mu C = 25*10^{-6}C

    Generally the energy required is mathematically represented as

                              E = \frac{k q_1 q_2 }{R}

    Where k is the coulomb constant with a value of  k = 9*10^9kg m^3 s^{-4} A^{-2}

           Substituting values we have

                             E = \frac{9*10^9 * 3*10^{-3}  * 25 *10^{-6}}{0.2}

                                E= 3.375*10^6J

    0
    2021-07-31T21:22:51+00:00

    Answer:

    3.37×10^6J

    Explanation:

    The external energy is given as KQ1Q2/r

    =(9*10^9)*(3*10^-3)*(25*10^-3)/(0.2)

    =3.375 *10^6 J

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