A charge of 0.80 nC is placed at the center of a cube that measures 4.0 m along each edge. What is the electric flux through one face of the

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A charge of 0.80 nC is placed at the center of a cube that measures 4.0 m along each edge. What is the electric flux through one face of the cube

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Thông Đạt 5 months 2021-08-14T05:28:26+00:00 1 Answers 40 views 0

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    2021-08-14T05:29:35+00:00

    Answer:

    The magnetic  flux is  \phi =  15 \ Nm^2 /C

    Explanation:

    From the question we are told that

        The value of the charge is  q =  0.80 \ nC =  0.80 *10^{-9} \ C

         The length of each side of  the cube is d = 4.0 \ m

    Generally the magnetic flux through a closed surface is  mathematically represented as

              \phi =  \frac{q}{\epsilon_o}  *  D

    Where  D is the area enclosing the charge

      Now  a  cube is made up of six faces but in this question we are considering only one face which is mathematically represented as

          D =  \frac{1}{6}

    So  the electric flux through one face of the cube  is  mathematically represented as

             \phi =  \frac{q}{6 *  \epsilon _o  }

    where  \epsilon _o is the permitivity of free space with value  

               \epsilon_o  =  8.85 *10^{-12} F/m

    substituting value  

          \phi =  \frac{0.80 *10^{-9}}{6 *  8.85 *10^{-12} }

         \phi =  15 \ Nm^2 /C

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