A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex? a)7/2 b)1/2 c)3/2

Question

A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex?
a)7/2
b)1/2
c)3/2
d)5/2

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Khoii Minh 6 months 2021-08-22T00:49:06+00:00 2 Answers 8 views 0

Answers ( )

    0
    2021-08-22T00:50:10+00:00

    Answer:

    D

    Step-by-step explanation:

    The equation is going to by

    y = (x – 2)(x – 3)         Multiply to remove the brackets.

    y = x^2 – 2x – 3x + 6

    y = x^2 – 5x + 6       Now what you are going to do is complete the square.

    y = (x^2 – 5x  +  __ ) +6

    Take – 5

    Divide it by 2 = -5 / 2

    and square it = (-5 / 2)^2 = 25/4

    Put this result inside the brackets.

    y = (x^2 – 5x + 25/4 ) + 6               Now subtract 25/4 after the 6

    y = (x^2 – 5x + 25/4) + 6 – 25/4

    y = (x – 5/2)^2 – 1/4

    The x coordinate of the vertex  is 5/2

    You could also do this by using x = -b/2a = – -5/2*1 = 5/2

    0
    2021-08-22T00:50:54+00:00

    1/2 b . explained – puzzle it down

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )