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A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex? a)7/2 b)1/2 c)3/2

Question

A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex?

a)7/2

b)1/2

c)3/2

d)5/2

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Mathematics
6 months
2021-08-22T00:49:06+00:00
2021-08-22T00:49:06+00:00 2 Answers
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## Answers ( )

Answer:D

Step-by-step explanation:The equation is going to by

y = (x – 2)(x – 3) Multiply to remove the brackets.

y = x^2 – 2x – 3x + 6

y = x^2 – 5x + 6 Now what you are going to do is complete the square.

y = (x^2 – 5x + __ ) +6

Take – 5

Divide it by 2 = -5 / 2

and square it = (-5 / 2)^2 = 25/4

Put this result inside the brackets.

y = (x^2 – 5x + 25/4 ) + 6 Now subtract 25/4 after the 6

y = (x^2 – 5x + 25/4) + 6 – 25/4

y = (x – 5/2)^2 – 1/4

The x coordinate of the vertex is 5/2

You could also do this by using x = -b/2a = – -5/2*1 = 5/2

1/2 b . explained – puzzle it down