A certain metal with atomic mass 2.4 × 10−25 kg has an interatomic bond with length 2.4 × 10−10 m and stiffness 45 N/m. What is the speed of

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A certain metal with atomic mass 2.4 × 10−25 kg has an interatomic bond with length 2.4 × 10−10 m and stiffness 45 N/m. What is the speed of sound in a rod made of this metal?

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Thanh Hà 3 years 2021-08-31T04:41:06+00:00 1 Answers 2 views 0

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  1. Eirian
    0
    2021-08-31T04:42:37+00:00
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    Given Information:

    Stiffness of the metal = s =  45 N/m

    Atomic mass of the metal = m  = 2.4×10⁻²⁵ kg

    Interatomic bond distance = d = 2.4×10⁻¹⁰ m

    Required Information:

    Speed of sound = v = ?

    Answer:

    v = 3286.3 m/s

    Explanation:

    The speed of the sound in a rod made of this metal can be found using the following equation

    v = √(s/m)*d

    Where s is the stiffness of the metal, m is the atomic mass of the metal, and d is the interatomic bond distance

    v = √(45/2.4×10⁻²⁵)*( 2.4×10⁻¹⁰)

    v = 3286.3 m/s

    Therefore, the speed of the sound in a rod made of this metal would be 3286.3 m/s

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